- Registrado
- 8 de Oct, 2019
1 + 1 = 2
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You dork, (-7)2 doesn't give -14, but 49.Just for fun I tried it with -6 and it doesn’t work.
Ver archivo adjunto 1601329
Those are exponents? Where was the ^??You dork, (-7)2 doesn't give -14, but 49.
Fuck. We don't use the ^ for the exponent here, I forgot.Those are exponents? Where was the ^??
So much for math being the universal language.Fuck. We don't use the ^ for the exponent here, I forgot.
Generally we write (-7)2 with the exponent on top. My mistake, sorry guys. I should have written it like that.
You mean like (-7)²? Why not just type that then?Fuck. We don't use the ^ for the exponent here, I forgot.
Generally we write (-7)2 with the exponent on top. My mistake, sorry guys. I should have written it like that.
You Americans write everything strange, even Math. You barbarians don't even use the metric system.So much for math being the universal language.![]()
HOW DID YOU DO IT.You mean like (-7)²? Why not just type that then?
2 + 2 = 5 quick maths
I just copy-pasted in a unicode superscript: e.g. ², ³, ⁴, ⁵, and so on.HOW DID YOU DO IT.
I tried typing it like that here but I can only get (-7)2
LATEX MOTHERFUCKER DO YOU SPEAK ITShow or disprove the following:
FOR ALL x (EXISTS y (-Q(x, (f(y)) AND (P(x) -> EXISTS y R(y)) AND P(x)) <=> FORALL x EXISTS y ((-Q(x, f(y)) AND R(y)) AND P(x))
Show or disprove the following:
FOR ALL x (EXISTS y (-Q(x, (f(y)) AND (P(x) -> EXISTS y R(y)) AND P(x)) <=> FORALL x EXISTS y ((-Q(x, f(y)) AND R(y)) AND P(x))
Okey-dokie!LATEX MOTHERFUCKER DO YOU SPEAK IT
IVE JUST BEEN DABBED ON HELPOkey-dokie!
Ver archivo adjunto 1601419
I think the brackets might be a bit iffy though (entered verbatim).