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Seems to check out.(1+2+3+4+5+...+n)² = 1³+2³+3³+4³+5³+...+n³
The first n numbers sum up to n(n+1)/2; the first n cubes sum up to the square of that, i.e. n²(n+1)²/4. Both formulas are easily proved by induction.Is this actually proven or is it just one of those conjectures where we just haven't found an exception?
This still works, by the way. I specifically learned this song under the same motivation:He […] would sing it at parties to pick up chicks. It didn't even originally have French lyrics. He just sang vaguely French-sounding gibberish.